Calculate the horizontal and vertical components of a 280 N force pulling upwards at an angle of 33 degrees to the horizontal ?
To find the horizontal and vertical components of the force, you can apply some trigonometry.
First, let's define the force as F = 280 N. The angle between the force and the horizontal plane is 33 degrees.
The vertical component (Fv) can be found using the sine function:
Fv = F * sin(angle)
Fv = 280 N * sin(33 degrees)
Fv ≈ 280 N * 0.5547
Fv ≈ 155.29 N
The horizontal component (Fh) can be found using the cosine function:
Fh = F * cos(angle)
Fh = 280 N * cos(33 degrees)
Fh ≈ 280 N * 0.8315
Fh ≈ 232.22 N
Therefore, the vertical component is approximately 155.29 N, and the horizontal component is approximately 232.22 N.
Fx = 280*Cos33o
Fy = 280*sin33o
H C = 234.83N
V C = 152.50N