A liquid spray of mass 384 g is packed in a cylindrical container of internal radius 3.2cm. Given that the density of the liquid is 0.6g/cm3, calculate to 2 decimal places the height of liquid in the container.
.6/1 = 384/x
x = 384/.6 = 640
the gas occupies 640 cm^3 in the can
volume of can = πr^2 h
π(3.2^2)h = 640
h = 640/(10.24π) = 19.89 cm
the volume of the liquid of height h is
v = πr^2*h
also,
v = (384g)/(0.6g/cm^3)
So, equate the two, plug in r, and solve for h.
To calculate the height of the liquid in the container, we can use the formula:
Volume of liquid = Mass of liquid / Density of liquid
Given:
Mass of liquid = 384 g
Density of liquid = 0.6 g/cm³
Internal radius of the container = 3.2 cm
First, let's convert the mass of the liquid to grams:
Mass of liquid = 384 g
Next, we can calculate the volume of the liquid using the formula for the volume of a cylinder:
Volume of liquid = π * (radius²) * height
Given:
Internal radius of the container = 3.2 cm
Rearranging the formula, we can solve for the height of the liquid:
height = Volume of liquid / (π * (radius²))
Substituting the given values into the formula:
height = 384 g / (0.6 g/cm³ * π * (3.2 cm)²)
Calculating:
height ≈ 384 / (0.6 * 3.1416 * 3.2²) cm
height ≈ 32.04 cm
Therefore, the height of the liquid in the container is approximately 32.04 cm.
To calculate the height of the liquid in the container, we need to use the formula for volume of a cylinder:
V = πr^2h
First, let's convert the radius from centimeters to meters:
Radius (r) = 3.2 cm = 0.032 m
Next, we need to calculate the volume of the liquid:
V = mass / density
V = 384 g / 0.6 g/cm^3
Now, let's convert the units to match the radius:
V = 384 g / 0.6 g/cm^3 * (1 cm^3 / 1 mL) * (1 L / 1000 mL) * (1 m^3 / 1000 L)
Simplifying the equation:
V = 640 mL * (1 L / 1000 mL) * (1 m^3 / 1000 L)
V = 0.640 m^3
We now have the volume of the liquid.
Plugging in the values to the formula for volume of a cylinder:
0.640 = π * (0.032)^2 * h
Now we can solve for the height (h):
0.640 = π * 0.001024 * h
h = 0.640 / (π * 0.001024)
h ≈ 196.2 meters
Therefore, the height of the liquid in the container is approximately 196.2 meters.