The potential energy of a catapult was completely converted into kinetic energy by releasing a small stone with a mass of 20 grams. The velocity of the stone when it reached the target was 15.0 meters/second. What was the value of the kinetic energy of the stone when it reached the target?
Calculate the distance between two points A(3,4) and B(2,1)
(0.01) x (225) = 2.25 joules
To find the kinetic energy of the stone when it reached the target, we first need to calculate its mass.
Given:
Mass of the stone (m) = 20 grams
In order to convert grams to kilograms, we divide by 1000 (since 1 kilogram is equal to 1000 grams).
Mass of the stone (m) = 20 grams ÷ 1000 = 0.02 kilograms
Now, we can use the formula for kinetic energy:
Kinetic Energy (KE) = 1/2 * mass * velocity^2
Substituting the values into the formula, we have:
Kinetic Energy = 1/2 * 0.02 kg * (15.0 m/s)^2
Calculating further:
Kinetic Energy = 1/2 * 0.02 kg * 225 m^2/s^2
Kinetic Energy = 0.01 kg * 225 m^2/s^2
Kinetic Energy = 2.25 kg m^2/s^2
Kinetic Energy = 2.25 Joules
Therefore, the kinetic energy of the stone when it reached the target was 2.25 Joules.
To calculate the kinetic energy of an object, you can use the equation:
Kinetic Energy = (1/2) * mass * velocity^2
In this case, the mass of the stone is given as 20 grams, which needs to be converted to kilograms:
20 grams = 20/1000 = 0.02 kilograms
The velocity of the stone is given as 15.0 meters/second.
Now, we can plug these values into the formula:
Kinetic Energy = (1/2) * 0.02 kg * (15.0 m/s)^2
Calculating this expression, we get:
Kinetic Energy = (1/2) * 0.02 kg * (15.0 m/s)^2
= 0.01 kg * (225 m^2/s^2)
= 2.25 Joules
Therefore, the kinetic energy of the stone when it reached the target was 2.25 Joules.