Ammonium hydrogen phosphate, a common fertilizer, is made from reacting phosphoric acid with ammonia (NH3). If 10.00g of ammonia react, how many grams of fertilizer will be produced?
To determine the number of grams of fertilizer produced, we need to know the balanced chemical equation for the reaction between phosphoric acid and ammonia. Without this information, we cannot accurately calculate the amount of fertilizer produced.
Please provide the balanced chemical equation for the reaction, and I will be happy to assist you further.
To determine the grams of fertilizer produced, we need to set up a balanced chemical equation for the reaction between phosphoric acid and ammonia. The balanced equation is:
3NH3 + H3PO4 -> (NH4)3PO4
From the equation, we can see that 3 moles of ammonia (NH3) react with 1 mole of phosphoric acid (H3PO4) to produce 1 mole of ammonium hydrogen phosphate ((NH4)3PO4).
To find the grams of fertilizer produced from 10.00g of ammonia, we need to go through several steps:
1. Convert grams of ammonia to moles:
Using the molar mass of ammonia (NH3), which is approximately 17.03 g/mol, we can calculate the number of moles of ammonia:
moles of ammonia = mass of ammonia / molar mass of ammonia
= 10.00g / 17.03 g/mol
2. Apply the mole ratio between ammonia and ammonium hydrogen phosphate:
From the balanced equation, we can see that 3 moles of ammonia react to produce 1 mole of ammonium hydrogen phosphate. Therefore, we can use the following conversion factor:
3 moles of ammonia / 1 mole of (NH4)3PO4
3. Convert moles of ammonium hydrogen phosphate to grams:
To find the mass of ammonium hydrogen phosphate produced, we need to multiply the number of moles by the molar mass of (NH4)3PO4. The molar mass of ammonium hydrogen phosphate is approximately 149.1 g/mol.
mass of (NH4)3PO4 = moles of (NH4)3PO4 * molar mass of (NH4)3PO4
Putting it all together, the calculation looks like this:
mass of (NH4)3PO4 = (10.00g / 17.03 g/mol) * (1 mole of (NH4)3PO4 / 3 moles of ammonia) * (149.1 g/mol)
Simplifying the calculation will provide you with the answer in grams.
NH3 + H3PO4 ==> NH4H2PO4
mols NH3 = grams/molar mass
mols NH3 = mols NH4H2PO4 (from the 1:1 ratio in the balanced equation)
g NH4H2PO4 = mols NH4H2PO4 x molar mass NH4H2PO4