How many joules of energy are released when 45.0g of water cools from 18.0C to 70.0C? Specific heat of water is 4.184J/gC.

Water COOLS when it goes from 18 to 70 C? Strange.

To calculate the energy released when a substance cools or heats up, you need to use the formula:

Q = m * c * ΔT

Where:
Q = Energy released (in joules)
m = Mass of the substance (in grams)
c = Specific heat capacity of the substance (in joules/gram°C)
ΔT = Change in temperature (final temperature - initial temperature) (in °C)

Given values:
m = 45.0g
c = 4.184J/g°C
ΔT = 70.0°C - 18.0°C = 52.0°C

Substituting the given values in the formula:

Q = 45.0g * 4.184J/g°C * 52.0°C

Q = 9471.12 Joules

Therefore, when 45.0g of water cools from 18.0°C to 70.0°C, a total of 9471.12 Joules of energy is released.

heat=45*4.18*52 Joules