A weight suspended from a spring is seen to bob up and down over a distance of 11 cm twice each second.

What is its frequency? Answer in units of Hz.
002 (part 2 of 3) 10.0 points
What is its period? Answer in units of s.
003 (part 3 of 3) 10.0 points
What is its amplitude? Answer in units of cm.

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To find the frequency, period, and amplitude of the weight suspended from a spring, we can use the following formulas and information:

Frequency (f) = 1 / Period (T)
Period (T) = 1 / Frequency (f)
Amplitude (A) = Maximum displacement from equilibrium position

Given information:
Distance (d) = 11 cm
Number of oscillations per second = 2

To find the frequency:
Frequency (f) = Number of oscillations per second
Frequency (f) = 2 Hz

To find the period:
Period (T) = 1 / Frequency (f)
Period (T) = 1 / 2
Period (T) = 0.5 s

To find the amplitude:
Amplitude (A) = Maximum displacement from equilibrium position
Amplitude (A) = Distance (d) / 2
Amplitude (A) = 11 cm / 2
Amplitude (A) = 5.5 cm

Answer:
The frequency of the weight suspended from the spring is 2 Hz.
The period of the weight suspended from the spring is 0.5 s.
The amplitude of the weight suspended from the spring is 5.5 cm.