find the area of a triangle whose vertices have coordinates:(5,5)(3,4)(8,3)
There are many ways to do this, you will have to tell me at what level of math this is.
e.g. Have you heard of Heron's Formula?
e.g. do you know the cosine law?
What grade level is this ?
I get 7/2
simplest way, list the points counterclock-wise, repeating the first point you started with
5 5
3 4
8 3
5 5
area = (1/2)(sum of down-products - sum of up-products)
= (1/2)(20+9+40 - (15+32+15))
= (1/2)(7)
= 7/2 , just as Steve had
btw, this method works for any convex polygon
To find the area of a triangle with given vertices, you can use the formula for the area of a triangle when its coordinates are known. Let's break it down step by step:
Step 1: Write down the coordinates of the given vertices:
V1: (5, 5)
V2: (3, 4)
V3: (8, 3)
Step 2: Use the formula to calculate the area:
Area = 1/2 * |(x1 * (y2 - y3) + x2 * (y3 - y1) + x3 * (y1 - y2))|
Let's substitute the vertex coordinates into the formula:
Area = 1/2 * |(5 * (4 - 3) + 3 * (3 - 5) + 8 * (5 - 4))|
Simplifying,
Area = 1/2 * |(5 * 1 + 3 * -2 + 8 * 1)|
Area = 1/2 * |(5 - 6 + 8)|
Area = 1/2 * |(7)|
Area = 1/2 * 7
Area = 3.5 square units
So, the area of the triangle with the given vertices is 3.5 square units.