Vector AB whose tail is at (-4,2) and whose head is at (-1,3).

Calculate the magnitude of Vector AB.

here, x1 = - 1 y1 = 3

x2= - 4 y2 = 2

Vector AB= ( x2 - x1 y2 - y1)
=(-4 + 1 2 - 3)
=(- 3, - 1 )
x. component = - 3 , y component = - 1
magnitude = root under (x comp)2 + (y comp)2
= root under 9 +1
= root 10 units
Help me with chemistry please if you can . I just posted a question.. name : saurav

To calculate the magnitude of a vector AB, you need to find the distance between its tail and head. In this case, the tail of vector AB is at point A(-4, 2), and the head is at point B(-1, 3).

The magnitude of a vector can be calculated using the distance formula, which states:
magnitude = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Here, (x1, y1) represents the coordinates of point A, and (x2, y2) represents the coordinates of point B.

Let's substitute the values into the formula and solve for magnitude:

magnitude = sqrt((-1 - (-4))^2 + (3 - 2)^2)
= sqrt((3)^2 + (1)^2)
= sqrt(9 + 1)
= sqrt(10)

Therefore, the magnitude of vector AB is √10.