A neighbourhood requires 1.5 x 10^5 w of electricity to power all homes during peak usage times. A step-down transformer is used on the high voltage transmission lines to lower the voltage to 120v for household use. There are 25000 primary coils and 140 secondary coils on the transformer. What current flows through the high voltage transmission lines during this time?
P = Es*Is = 150,000 Watts
120*Is = 150,000
Is = 1250 Amps. = Current flowing through secondary coils.
Ip = 140/25000 * 1250 = 7 Amps = current
through primary coils and transmission lines.
To find the current flowing through the high voltage transmission lines, we can use the formula:
Current (I) = Power (P) / Voltage (V)
Given that the power required is 1.5 x 10^5 W (watts) and the voltage is not directly provided, but we know that the voltage is stepped down to 120 V (volts) for household use.
Now, let's find the high voltage by using the transformer ratio. The transformer ratio is given by:
Primary Coils (NP) / Secondary Coils (NS) = Primary Voltage (VP) / Secondary Voltage (VS)
We are given that there are 25,000 primary coils (NP) and 140 secondary coils (NS). Let's denote the primary voltage as VP and the secondary voltage as VS.
Using the given values:
25,000 / 140 = VP / 120
Simplifying this equation, we can find the primary voltage:
VP = (25,000 / 140) * 120
Now, we have the value for primary voltage (VP), which we can substitute into the power formula to find the current:
I = 1.5 x 10^5 W / VP
Calculating this expression will give us the current flowing through the high voltage transmission lines during peak usage times.