what is the mass percentage if you dissolve 0.659 mol of citric acid, C6H8O7, in 1.00 kg of water.
figure the mass of the .659 mol of citric acid.
mass percent=masscitric/(total mass) * 100
To calculate the mass percentage, we need to determine the mass of the citric acid and the mass of the solution.
First, let's determine the mass of the citric acid. To do this, we need to know the molar mass of citric acid (C6H8O7).
The molar mass of carbon (C) is 12.01 g/mol, the molar mass of hydrogen (H) is 1.01 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol.
The molar mass of citric acid (C6H8O7) can be calculated as follows:
(6 * molar mass of carbon) + (8 * molar mass of hydrogen) + (7 * molar mass of oxygen)
= (6 * 12.01) + (8 * 1.01) + (7 * 16.00)
= 72.06 + 8.08 + 112.00
= 192.14 g/mol
Now, let's calculate the mass of 0.659 mol of citric acid:
mass of citric acid = 0.659 mol * 192.14 g/mol
= 126.50 g
Next, let's determine the mass of the solution. We are given that the solution contains 1.00 kg (1000 g) of water.
Finally, we can calculate the mass percentage:
mass percentage = (mass of solute / mass of solution) * 100
= (126.50 g / (126.50 g + 1000 g)) * 100
= (126.50 g / 1126.50 g) * 100
≈ 11.23%
Therefore, the mass percentage of the citric acid in the solution is approximately 11.23%.