The average of two numbers is 81. The difference between the number is 26. What is the smaller number?
Please help me to solve this....
The average of two numbers is 81. The difference between the number is 26. What is the smaller number?
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To find the smaller number, let's consider:
Let's assume the two numbers are x and y (with x being the smaller number).
According to the given information:
1. The average of two numbers is 81.
The average of two numbers can be calculated by summing the numbers and dividing by 2. So we have:
(x + y) / 2 = 81
2. The difference between the numbers is 26.
The difference between two numbers can be calculated by subtracting the smaller number from the larger number. So we have:
y - x = 26
To solve for x, we can use the second equation to express y in terms of x:
y = x + 26
Substituting this value of y into the first equation, we can solve for x:
(x + (x + 26)) / 2 = 81
(2x + 26) / 2 = 81
2x + 26 = 162
2x = 162 - 26
2x = 136
x = 136 / 2
x = 68
Therefore, the smaller number is 68.