After Khalil gave Benjamin 3/5 of the rocks in his collection, Benjamin had 70 rocks. If Benjamin had 25 rocks in the beginning, how many rocks did Khalil have in the beginning?
(70 - 25) = 3/5x
Solve for x.
To determine how many rocks Khalil had in the beginning, we can work backwards from the information given.
We know that after Khalil gave Benjamin 3/5 of his rocks, Benjamin had a total of 70 rocks. So, if Benjamin had 25 rocks in the beginning, he received 70 - 25 = 45 rocks from Khalil.
Since Benjamin received 3/5 of Khalil's rocks, we can set up the following equation:
3/5 * Khalil's initial number of rocks = 45
To find the initial number of rocks Khalil had, we need to isolate Khalil's initial number of rocks on one side of the equation.
To do this, we can multiply both sides of the equation by 5/3:
(5/3) * (3/5) * Khalil's initial number of rocks = (5/3) * 45
The 5/3 on the left side cancels out, leaving:
Khalil's initial number of rocks = 75
Therefore, Khalil had 75 rocks in the beginning.