(Triangle ABC is scalene) AC is a straight shore line and B is a boat out at sea. Angle A is 60 degrees and Angle C is 45 degrees. Find the shortest distance from the boat to the shore if A and C are 5km apart...I honestly have no idea where to start with this. I drew it out, but it's not a right triangle, so I can't use sine, cosine, or tangent...

First of all, my approach was to use sine rule. We all know that DB would be the shortest distance. In order to find that, we need to know either AB or BC,

First of all, my approach was to use law of sine. We all know that DB would be the shortest distance. In order to find that, we need to know either AB or BC,

so i find AB, AB = (sin45/ sin 75) x 5 = 3.66 ,
and then we find BD

sin 60 = BD/AB
BD= 3.66 x sin60 = 3.17km ( Approximately)

Ahoy there! Don't worry, I've got a trick up my sleeve for this one! Since we're dealing with a scalene triangle, we can't use the usual trigonometric functions directly, but fear not, for the Law of Sines has come to our rescue!

The Law of Sines states that in any triangle, the ratio of a side to the sine of its opposing angle is constant. In this case, we can use it to find the shortest distance from the boat to the shore.

First, let's label the sides of the triangle. We'll call the side opposite angle A "a," the side opposite angle B (which is the shortest distance we're trying to find) "b," and the side opposite angle C "c." We know that angle A is 60 degrees, angle C is 45 degrees, and side AC is 5 km.

Now, we can set up the Law of Sines equation:

sin(A) / a = sin(C) / c

Substituting in the given values, we get:

sin(60) / 5 = sin(45) / b

Now, we can solve for b. Using a bit of mathematical magic:

b = (5 * sin(45)) / sin(60)

Plug that into your trusty calculator, and you'll find that the shortest distance from the boat to the shore is approximately 3.54 km.

Hope that helps, and happy sailing!

To find the shortest distance from the boat to the shore, we can use the concept of trigonometry and apply the Law of Sines. Although the triangle is not a right triangle, the Law of Sines can still be used to determine the length of any side.

1. Start by labeling the given information:
- Side AC = 5 km (the distance between point A and point C)
- Angle A = 60 degrees
- Angle C = 45 degrees

2. Since we want to find the shortest distance from the boat to the shore, we are interested in the side opposite angle A. Let's call this side "a" (the side opposite angle A) and the distance from the boat to the shore "b". The side opposite angle C will be "c".

3. Apply the Law of Sines, which states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is constant.
- In our case, it would be: a/sin A = c/sin C

4. Rearrange the equation to solve for side a:
a = (c * sin A) / sin C

5. Substitute the known values into the equation:
a = (5 km * sin 60 degrees) / sin 45 degrees

6. Calculate the value of sin 60 degrees and sin 45 degrees using a scientific calculator or a trigonometry table if needed. These values are approximately √3/2 and √2/2, respectively.

7. Plug in the values into the equation:
a = (5 km * (√3/2)) / (√2/2)
a = (5 km * (√3/2)) * (2/√2)
a = (5 km * (√3/√2))
a = (5 km * (√3√2/2))
a = (5 km * √6/2)
a = (5 km * √6)/2

The result will give you the shortest distance from the boat to the shore. However, since this is an approximate value and not simplified, it's best to leave the answer in this form or use a calculator for a more precise decimal approximation.

If the point in question is D, then we have

AD+DC = 5

BD/AD = tan 60°
BD/DC = tan 45°

so, we have

BD/√3 + BD/1 = 5
Now just solve for BD, the desired distance.