The radiator in your car uses either water or ethylene glycol (anti-freeze) to remove heat from the engine and dissipate it to the outside air. If the water recirculation rate is 17.0 kg per minute of water and the water temperature leaving the engine and entering the radiator is 86.0 C and the temperature of the water leaving the radiator and entering the engine is 46.0 C, then how much energy (kJ) is dissipated by the radiator per minute? The specific heat capacity of water is 4.18 J/g ·K. The units are kJ/minute. The error interval is +/- 5%.

Assuming the fluid is H2O and not ethylene glycol, then

q in joules = mass H2O x specific heat H2O x (Tfinal-Tinitial)
and I would substitute 17,000 g for mass H2O

so i did 17000 x4.18x(86-46)=284 is that what you meant

Yes, it's what I meant but 284 isn't the right answer if that is 284 J/min. Punch those numbers into the calculator again and remember the answer should be in kJ.

To calculate how much energy is dissipated by the radiator per minute, we need to use the equation:

Energy dissipated = mass flow rate × specific heat capacity × temperature difference

First, let's convert the given values to the correct units:

The mass flow rate is given as 17.0 kg per minute. We'll keep it as it is since it's already in the correct unit.

The specific heat capacity of water is given as 4.18 J/g·K. We need to convert it to kJ/kg·K, so we divide by 1000:
specific heat capacity = 4.18 J/g·K / 1000 = 0.00418 kJ/g·K

The temperature difference is (86.0 - 46.0) C = 40.0 C.

Now, we can calculate the energy dissipated by the radiator per minute using the equation:

Energy dissipated = 17.0 kg/min × 0.00418 kJ/g·K × 40.0 C

Energy dissipated = 2.2636 kJ/min

However, we need to consider the error interval of +/- 5%. To calculate the minimum and maximum values, we use:

Minimum energy dissipated = Energy dissipated - (error interval × Energy dissipated)
Maximum energy dissipated = Energy dissipated + (error interval × Energy dissipated)

Minimum energy dissipated = 2.2636 kJ/min - (0.05 × 2.2636 kJ/min)
Minimum energy dissipated = 2.2636 kJ/min - 0.1132 kJ/min
Minimum energy dissipated = 2.1504 kJ/min

Maximum energy dissipated = 2.2636 kJ/min + (0.05 × 2.2636 kJ/min)
Maximum energy dissipated = 2.2636 kJ/min + 0.1132 kJ/min
Maximum energy dissipated = 2.3768 kJ/min

So, the energy dissipated by the radiator per minute is approximately 2.2636 kJ/min, with a minimum value of 2.1504 kJ/min and a maximum value of 2.3768 kJ/min (due to the +/- 5% error interval).