a bullet is fired horizontally from the top of a cliff that is 15 m above a long lake. if the muzzle speed is 478, how far from the bottom of the cliff does the bullet strike the surface of the lake
h = 15 m
Xo = 478 m/s? = Initial hor. speed.
h = 0.5g*t^2 = 15 m
4.9t^2 = 15
t^2 = 3.06
Tf = 1.75 s.Fall time.
Dx = Xo*Tf = 478m/s * 1.75s = 836 m.
From bottom of cliff.