Express your answers as simplifier, improper fraction if necessary
[3(a+3)]=29
the solution set is { }
3a + 9 = 29
3a = 29-9
3a = 20
a = 20/3
a = 6.6
round off to 7
I asked for a possible improper fraction, so I would leave it as
a = 20/3
To solve the equation [3(a + 3)] = 29 for the variable "a," you can follow these steps:
1. Simplify the expression in the brackets: [3(a + 3)] becomes 3a + 9.
2. Set the simplified expression equal to 29: 3a + 9 = 29.
3. Subtract 9 from both sides of the equation to isolate the term with "a": 3a = 29 - 9, which simplifies to 3a = 20.
4. To solve for "a," divide both sides of the equation by 3: a = 20 / 3.
The solution for "a" is a = 20/3. This is an improper fraction, which means the numerator (20) is greater than the denominator (3). However, if you prefer a mixed number representation, you can divide 20 by 3, which equals 6 with a remainder of 2. Therefore, the simplifier, improper fraction becomes a = 6 2/3.