The lists below show the players who will be competing in two different games.Both games are pure chance;it is equally probable for any player to with either game.
Game 1:Jen,Fred,Monique,Darryn
Game 2:Craig,Sarah,Yvonne,Allan
What is the probability that Craig will win both games?
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
(1/4)^2 = ?
To find the probability that Craig will win both games, we need to determine the total number of possible outcomes for both games and the number of favorable outcomes for Craig winning both games.
Since each game is pure chance, all players have an equal probability of winning. Therefore, the probability of Craig winning each game is 1 out of the total number of players in that game.
Game 1 has 4 players, so the probability of Craig winning Game 1 is 1/4.
Similarly, Game 2 has 4 players, so the probability of Craig winning Game 2 is also 1/4.
To find the probability of two independent events happening, we multiply their probabilities. Therefore, the probability of Craig winning both games is:
P(Craig winning Game 1) * P(Craig winning Game 2) = 1/4 * 1/4 = 1/16.
So, the probability that Craig will win both games is 1/16 or 0.0625.