2/5c+4/5c-6=c+7 6/5c=c-13 5/5c=-13 C=-13

Did you sub c = -13 back in to see if it works ??

I bet it won't, since I see a blatant error in your 2nd last line

Hint: don't you think that little c should be changed to 5c/5 ?
Don't you need a common denominator to subtract ?

C=65

correct

Thanks

To solve the equation 2/5c + 4/5c - 6 = c + 7, you need to combine like terms and isolate the variable c.

First, let's combine the terms with c on the left-hand side of the equation:
2/5c + 4/5c - 6 = c + 7

To combine the terms with c, we can add the coefficients:
(2/5 + 4/5)c - 6 = c + 7

Simplifying the coefficients:
(6/5)c - 6 = c + 7

Next, let's isolate the variable c by getting rid of the fractions.
To eliminate the fraction, we can multiply both sides of the equation by the denominator of the fractions, which is 5:
5 * (6/5)c - 5 * 6 = 5 * (c + 7)

Simplifying:
6c - 30 = 5c + 35

To isolate the variables on one side and the constant terms on the other side, we can subtract 5c from both sides:
6c - 5c - 30 = 5c - 5c + 35

Simplifying:
c - 30 = 35

Next, let's isolate the variable c. We can do this by adding 30 to both sides of the equation:
c - 30 + 30 = 35 + 30

Simplifying:
c = 65

Therefore, the value of c is 65.