A cup of coffee milk is 35% coffee syrup with a second cup of coffee milk that is 65% coffee syrup. How many kilograms of each cup of coffee milk must be combined to get 20 kilograms of coffee milk that is 41% coffee syrup
amount of the 35% stuff --- x kg
amount of the 65% stuff --- 20 - x kg
.35x + .65(20-x) = .41(20)
multiply by 100
35x + 65(20-x) = 820
35x + 1300 - 65x = 820
-30x = -480
x = 16 kg
you state the conclusion
Totally lost.
What grade level are you in
This is a rather straighforward problem.
I am a senior failing this class last chance to make it up by graduation. Can't do diploma plus either. Thanks anyway. Lost cause I guess
To solve this problem, we can use a system of linear equations. Let's assume x represents the amount of 35% coffee syrup and y represents the amount of 65% coffee syrup.
We're given two pieces of information:
1. The total amount of coffee milk is 20 kilograms.
x + y = 20 (equation 1)
2. The resulting coffee milk is 41% coffee syrup.
(0.35x + 0.65y) / 20 = 0.41 (equation 2)
To solve this system of equations, we can use the substitution or elimination method. Let's solve it using the substitution method.
From equation 1, we can express x in terms of y:
x = 20 - y
Now, substitute this value of x in equation 2:
(0.35(20 - y) + 0.65y) / 20 = 0.41
Simplifying the equation:
(7 - 0.35y + 0.65y) / 20 = 0.41
7 + 0.3y = 8.2
0.3y = 1.2
y = 4
Now, substitute this value of y back into equation 1 to find x:
x + 4 = 20
x = 16
Therefore, you need 16 kilograms of the 35% coffee syrup and 4 kilograms of the 65% coffee syrup to make 20 kilograms of coffee milk that is 41% coffee syrup.