Uniform Motion Related Problem
Two cars, 210 km apart, met each other in 2 hours. If one car travelled at 60 kph, at what rate did the second car travel?
d1 + d2 = 210 km
60*2 + r2*2 = 210
Solve for r2.
To solve this problem, we can use the concept of relative speed. Relative speed is the difference in speed between two objects moving in the same direction or opposite directions.
Let's define:
- Speed of the first car as x kph (since it is not given)
- Speed of the second car as y kph (what we need to find)
Given that the first car traveled at 60 kph, we can set up the equation:
Distance covered by the first car = 60 kph x time taken
Distance covered by the second car = y kph x time taken
Since the two cars met each other, the sum of their distances should be equal to the total distance between them:
Since the total distance between the two cars is 210 km, we have:
60 kph x 2 hours + y kph x 2 hours = 210 km
Simplifying the equation, we get:
120 kph + 2y kph = 210 km
Now, we can solve for y:
2y kph = 210 km - 120 kph
2y kph = 90 km
y kph = 90 km / 2
y kph = 45 kph
Therefore, the second car traveled at a rate of 45 kph.