From a survey of 100 college students, a marketing research company found that 70 students owned iPods, 50 owned cars, and 40 owned both cars and iPods.
(a) How many students owned either a car or an iPod (but not both)?
70 - 40 = 30
50 - 40 = 10
simplify:4*5^2-2
To find the number of students who owned either a car or an iPod (but not both), we need to add the number of students who owned cars and the number of students who owned iPods, and then subtract the number of students who owned both.
Let's follow these steps to calculate the answer:
Step 1: Determine the number of students who owned cars: 50
Step 2: Determine the number of students who owned iPods: 70
Step 3: Determine the number of students who owned both cars and iPods: 40
Step 4: Add the number of students who owned cars and the number of students who owned iPods: 50 + 70 = 120
Step 5: Subtract the number of students who owned both cars and iPods from the total obtained in step 4: 120 - 40 = 80
Therefore, 80 students owned either a car or an iPod (but not both).
To determine the number of students who owned either a car or an iPod (but not both), we need to subtract the number of students who owned both from the total number of students who owned either a car or an iPod.
We are given that 70 students owned iPods, 50 owned cars, and 40 owned both cars and iPods.
To find the number of students who owned either a car or an iPod, we add the number of students who owned only iPods to the number of students who owned only cars. So:
Number of students who owned either a car or an iPod = Number of students who owned only iPods + Number of students who owned only cars
Number of students who owned either a car or an iPod = (Number of students who owned iPods) + (Number of students who owned cars) - (Number of students who owned both cars and iPods)
Number of students who owned either a car or an iPod = 70 + 50 - 40
Number of students who owned either a car or an iPod = 80
Therefore, 80 students owned either a car or an iPod (but not both).