A 500 kg car experiences a frictional force of 3208 N while turning, if the car is traveling around a turn of radius 16 m what is the velocity of the car?
v^2/r=3208/500
solve for v.
centripetal scceleartion=force/mass
To find the velocity of the car, we need to use the concept of centripetal force:
The centripetal force required to keep an object moving in a circular path is given by the formula:
F = (m * v^2) / r
where:
F is the centripetal force
m is the mass of the object
v is the velocity of the object
r is the radius of the circular path
In this case, we already know the values of m (mass of the car) and r (radius of the turn). We need to find the value of v (velocity of the car). Rearranging the formula, we get:
v^2 = (F * r) / m
Now, let's plug in the values:
F = 3208 N (frictional force)
m = 500 kg (mass of the car)
r = 16 m (radius of the turn)
Substituting these values, we have:
v^2 = (3208 * 16) / 500
v^2 = 102976 / 500
v^2 = 205.952
To find v, we take the square root of both sides:
v = √205.952
v ≈ 14.35 m/s
Therefore, the velocity of the car is approximately 14.35 m/s.