10g of hydrogen is burnt in the presence of excess oxygen.the mass of water formed is?
10G of hydrogen burnt in the presence of excess of oxygen, the mass of water is formed?
5*18=90g
To find the mass of water formed when 10g of hydrogen is burned in the presence of excess oxygen, we need to understand the chemical equation for the combustion of hydrogen:
2H₂ + O₂ → 2H₂O
From the equation, we can see that 2 moles of hydrogen react with 1 mole of oxygen to form 2 moles of water.
To determine the mass of water formed, we need to calculate the number of moles of hydrogen and then use the mole ratio to find the moles of water. Finally, we can convert the moles of water to mass using the molar mass of water.
1. Calculate the moles of hydrogen:
The molar mass of hydrogen (H₂) is 2g/mol.
Given mass of hydrogen = 10g.
Moles of hydrogen = mass of hydrogen / molar mass of hydrogen
Moles of hydrogen = 10g / 2g/mol = 5mol
2. Use the mole ratio to find the moles of water:
From the balanced equation: 2H₂O is formed from 2H₂
Moles of water = 2 × moles of hydrogen = 2 × 5mol = 10mol
3. Convert moles of water to mass:
The molar mass of water (H₂O) is 18g/mol.
Mass of water = moles of water × molar mass of water
Mass of water = 10mol × 18g/mol = 180g
Therefore, the mass of water formed when 10g of hydrogen is burned in the presence of excess oxygen is 180g.
196g
2H2 + O2 = 2H2O
10g of H2 is 5 moles.
Each mole of H2 produces a mole of H2O,
so, you will get 5 moles of water.
Just convert that to grams for the mass.