-3x+5y=80
4x-5y=-90
What are the x and y for both equations
iS x 10 and y 26
add the two equations as is
x = -10
5 y = 50
y = 10
Thank you
To find the values of x and y for the given equations, we can solve the system of equations using the method of elimination or substitution. Let's use the method of elimination:
Step 1: Multiply both sides of the first equation by 4 and the second equation by 3 to create opposite coefficients for y:
-12x + 20y = 320 (equation 1)
12x - 15y = -270 (equation 2)
Now, add equation 1 and equation 2:
(-12x + 20y) + (12x - 15y) = 320 + (-270)
-12x + 12x + 20y - 15y = 320 - 270
5y = 50
Step 2: Divide both sides of the equation by 5 to solve for y:
5y/5 = 50/5
y = 10
Step 3: Substitute the value of y into one of the original equations. Let's take the first equation:
-3x + 5(10) = 80
-3x + 50 = 80
Simplify:
-3x = 80 - 50
-3x = 30
Step 4: Divide both sides of the equation by -3:
(-3x)/-3 = 30/-3
x = -10
Therefore, the values of x and y for the given system of equations are:
x = -10
y = 10