A gas occupies 30 0dm3 at stp what volume would it occupy at 91 and 380mm hg?
91 what?
(P1V1/T1) = (P2V2/T2)
31.3057
To determine the volume of gas at different conditions, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (in Kelvin)
First, let's calculate the number of moles of gas at STP (Standard Temperature and Pressure). STP is defined as 0°C or 273.15 K and 1 atm.
Given:
V₁ = 300 dm³ (dm³ is equivalent to liters, which is the SI unit for volume)
T₁ = 273.15 K
P₁ = 1 atm
Using the ideal gas law, we can rearrange the equation to solve for n:
n = PV / RT
n = (1 atm) * (300 dm³) / (0.0821 L·atm/mol·K * 273.15 K)
Now, plug in all the values to calculate the number of moles of gas at STP.
n = 36.31 moles
Now, let's calculate the volume of gas at the given conditions (91 mmHg and 380 mmHg).
We can use the ratio of pressures to find the new volume. The equation is:
(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂
Where:
P₂ = 91 mmHg
P₁ = 1 atm
V₁ = 300 dm³
V₂ = volume we want to find
T₁ = 273.15 K
T₂ = temperature at the new condition
First, let's convert the given pressure to atm:
P₂ = 91 mmHg * (1 atm / 760 mmHg)
Now, plug in the values and solve for V₂:
(1 atm * 300 dm³) / (273.15 K) = (91 mmHg * V₂) / T₂
V₂ = (1 atm * 300 dm³ * T₂) / (91 mmHg * 273.15 K)
Similarly, you can repeat the above calculation for the condition of 380 mmHg.
Using these formulas and conversions, you can calculate the volume of gas at the given conditions of 91 mmHg and 380 mmHg.