hummingbirds beat their wings 1500 times in 30seconds calculate frequency and the period
F = 1500beats/30s = 50 Beats/s = 50cycles/s = 50 Hz.
P = 1/F = 1/50 = 0.02 s.
To calculate the frequency and period of hummingbird wingbeats, we can use the following formulas:
Frequency (f) = number of wingbeats (n) / time (t)
Period (T) = 1 / Frequency
Given:
Number of wingbeats (n) = 1500
Time (t) = 30 seconds
Let's calculate the frequency first:
f = n / t
f = 1500 / 30
f = 50 Hz
Therefore, the frequency of hummingbird wingbeats is 50 Hz, meaning they beat their wings 50 times per second.
Now, let's calculate the period:
T = 1 / f
T = 1 / 50
T = 0.02 seconds
Therefore, the period of hummingbird wingbeats is 0.02 seconds, which means it takes 0.02 seconds for one complete wingbeat cycle.