Balance and complete equation

H2SO4 + Na2CO3 ---> Na2SO4 + H2O + CO2

right.

To balance this chemical equation, you need to make sure that the number of atoms of each element is the same on both sides of the equation. Here's how you can do it:

H2SO4 + Na2CO3 → Na2SO4 + H2O + CO2

Let's start by counting the number of atoms on each side:

On the left side (reactants):
- Hydrogen (H): 2 atoms
- Sulfur (S): 1 atom
- Oxygen (O): 4 atoms
- Sodium (Na): 2 atoms
- Carbon (C): 1 atom

On the right side (products):
- Sodium (Na): 2 atoms
- Sulfur (S): 1 atom
- Oxygen (O): 5 atoms
- Hydrogen (H): 2 atoms
- Carbon (C): 1 atom

The equation is currently unbalanced, as the number of atoms is not the same on both sides.

To balance the equation, start by adjusting one element at a time, using coefficients. Let's begin with the hydrogen atoms:

H2SO4 + Na2CO3 → Na2SO4 + H2O + CO2

There are 2 hydrogen atoms on the left and 2 on the right. Therefore, the hydrogen atoms are already balanced.

Next, let's balance the oxygen atoms:

H2SO4 + Na2CO3 → Na2SO4 + H2O + CO2

On the left side, there are 4 oxygen atoms (2 from sulfuric acid and 2 from carbon dioxide), while on the right side, there are 5 oxygen atoms (4 from sodium sulfate and 1 from water). To balance the oxygen atoms, we need to add a coefficient of 5 in front of H2O:

H2SO4 + Na2CO3 → Na2SO4 + 5H2O + CO2

Now, let's balance the sodium atoms:

H2SO4 + Na2CO3 → Na2SO4 + 5H2O + CO2

On the left side, there are 2 sodium atoms, while on the right side, there are also 2 sodium atoms. Therefore, the sodium atoms are balanced.

Lastly, let's balance the sulfur and carbon atoms:

H2SO4 + Na2CO3 → Na2SO4 + 5H2O + CO2

To balance the sulfur atom, we need to add a coefficient of 1 in front of Na2SO4:

H2SO4 + Na2CO3 → Na2SO4 + 5H2O + CO2

To balance the carbon atom, we need to add a coefficient of 1 in front of CO2:

H2SO4 + Na2CO3 → Na2SO4 + 5H2O + CO2

The final balanced equation is:

H2SO4 + Na2CO3 → Na2SO4 + 5H2O + CO2