While you are in detention after school, your teacher tells you to slide a large, 89.7 kilogram box across the floor. The coefficient of static friction (ìstatic) between the box and the floor is 0.50. Compute the force parallel to the ground (F parallel)required to start accelerating the box

M*g = 89.7kg * 9.8N/kg = 879.1 N. = Wt.

of box = Normal force(Fn).

Fs = u*Fn = 0.5 * 879.1 = 439.5 N. =
Force of static friction.

Fap-Fs = M*a
Fap-439.5 = M*0 = 0
Fap = 439.5 N. = Force applied.

To compute the force parallel to the ground (F_parallel) required to start accelerating the box, we can use the equation:

F_parallel = ì_static * N

Where ì_static is the coefficient of static friction and N is the normal force exerted on the box.

To find the normal force, we need to consider the weight of the box. The weight (W) can be calculated using:

W = m * g

Where m is the mass of the box and g is the acceleration due to gravity (approximately 9.8 m/s^2).

Given that the mass of the box is 89.7 kilograms, we can calculate the weight:

W = 89.7 kg * 9.8 m/s^2
W = 878.46 N

Now, we can use the formula for F_parallel:

F_parallel = ì_static * N

Substituting the values:

F_parallel = 0.50 * 878.46 N
F_parallel ≈ 439.23 N

Therefore, to start accelerating the box, a force parallel to the ground of approximately 439.23 Newtons is required.