How long (in seconds) does it take to deposit 1.065e+001 g Zn on a steel gate when 2.375e+001 A are passed through a ZnSO4 solution?
I assume that is 10.65 g Zn with 23.75 A.
96,485 will deposit 65.38/n g Zn. That's 65.38/2 = 32.69 g Zn. You want 10.65g Zn. How many C is that?
C = 96,485 x 10.65/32.69 = ?
Then C = Amperes x seconds
You know C and A, solve for seconds.