The coefficient of static
friction between a skier and
the snow is 0.16, with a
coefficient of kinetic friction
of 0.13. The skier weighs
550N. How much force
directed parallel to the
horizontal surface is required
for the skier to start to move?
Known,
Us= 0.16
Uk=0.13
Wt=550N
Im not sure how to work the question out and was just looking for some guidance
M*g = 550 N. = Normal force(Fn).
Fs = u*Fn = 0.16 * 550 = 88 N. = Force
of static friction.
Fap-Fs = M*a
Fap - 88 = M*0 = 0
Fap = 88 N. = Force applied.
To find the force required for the skier to start moving, you can use the concept of static friction. The force required to overcome static friction and initiate movement is equal to the maximum value of static friction.
The formula for static friction is:
Fs = Us * W
Where:
Fs = force of static friction
Us = coefficient of static friction
W = weight of the skier (550 N)
Given that the coefficient of static friction (Us) is 0.16 and the weight of the skier (W) is 550 N, you can calculate the force of static friction:
Fs = 0.16 * 550
= 88 N
Therefore, the force required for the skier to start moving is 88 N.