Two kids of mass 10 kg and 15 kg are trying to balance a see saw of total length 6 metres with fulcrum at the centre if one of the kid is sitting aat on end the distance of other from the centre in metres is

well

10*3=15*x
solve for x

1.7

To balance a seesaw, the product of one side's weight and distance from the fulcrum should be equal to the product of the other side's weight and distance from the fulcrum. Since the fulcrum is at the center, the distance from the fulcrum to one end of the seesaw is half of the total length.

Let's assume that one child is sitting on one end of the seesaw, and the other child is sitting on the other end. Let's call the distance of the second child from the center x meters.

Since the total length of the seesaw is 6 meters and the fulcrum is at the center, the distance of the first child from the center is also 6/2 = 3 meters.

To balance the seesaw, the product of the weight and distance of one child should be equal to the product of the weight and distance of the other child.

Therefore, we have the equation:

10 kg * 3 m = 15 kg * x m

Now we can solve for x:

30 m = 15 kg * x m

Divide both sides of the equation by 15 kg:

30 m / 15 kg = x m

x = 2 m

Therefore, the distance of the second child from the center is 2 meters.