two complementary angles are drawn such that one angle is 10° more than seven times the other angle find the measur of each angle

let the smaller angle be x°

then the larger is 7x + 10

but ...
x + 7x + 10 = 180

take over

Let y° is the smallest angel Y° +7y°+ 10°=90° 8y°+10°=90° 8y°=90°_10°. 8y°=80° =10°

I believe the angles should sum to 90°

X+7x+10=90

8x+10=90
8x=90-10
8x\8=80\8
X=10

Y=7(10+10)
Y=70+10
Y=80

Y=10

Ow thanks

but what is the correct answer?😮😞
abebe or sophoniyas?

To find the measure of each angle, let's use algebraic expressions.

Let's assume one angle is x degrees. According to the given information, the other angle is 10° more than seven times the first angle. So, the second angle can be represented as 7x + 10.

Since complementary angles add up to 90 degrees, we can set up the following equation:

x + 7x + 10 = 90

Simplifying the equation:

8x + 10 = 90

Next, subtract 10 from both sides:

8x = 80

Now, divide both sides by 8:

x = 10

So, one angle is 10 degrees.

Now, substitute the value of x back into the equation to find the other angle:

Second angle = 7x + 10 = 7(10) + 10 = 70 + 10 = 80 degrees.

Therefore, one angle measures 10 degrees, and the other angle measures 80 degrees.

Thanks for the correction , Steve

7493h

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the answer is 27