The heights of the trees in a forest are normally distributed, with a mean of 25 meters and a standard deviation of 6 meters. What is the probability that a randomly selected tree in the forest has a height greater than or equal to 37 meters? Use the portion of the standard normal table given to help answer the question

2.3

use this probability calculator instead of tables

Just enter the date, and click on the greater than option
http://davidmlane.com/hyperstat/z_table.html

you should get .0228

2.3

To find the probability that a randomly selected tree in the forest has a height greater than or equal to 37 meters, we can use the standard normal distribution.

First, we need to standardize the value 37 using the formula z = (x - μ) / σ, where x is the value we want to standardize, μ is the mean, and σ is the standard deviation.

In this case, x = 37, μ = 25, and σ = 6. Plugging these values into the formula, we get:

z = (37 - 25) / 6
z = 12 / 6
z = 2

Next, we need to find the area under the standard normal curve to the right of z = 2. We'll use the portion of the standard normal table given.

From the table, we find that the area to the left of z = 2 is approximately 0.9772.

To find the area to the right of z = 2, we subtract the area to the left of z = 2 from 1:

Area to the right = 1 - 0.9772
Area to the right = 0.0228

Therefore, the probability that a randomly selected tree in the forest has a height greater than or equal to 37 meters is approximately 0.0228, or 2.28%.