posted by an .
a solution is made by dissolving 25 g NaCl in enough water to make 1.0 L solution. Assume that density of the solution is 1.0 g/mL. calculate the mass percent, molarity, molality, and mole fraction of NaCl.
25g/58.44g NaCl=.428 mol
1000 grams of solvent H20
25g/58,44 g x100= 42.8 % mass percent
molarity .428 mol/1.0 L= .428 M
molality= .428 mol/1 Kg= .428 molal is that right?