Solve the system of two equations
2y=8 and 15y=2x-4
If 2y = 8, then y = 4.
Substitute that value into the second equation to find x.
15y= 24-4
To solve the system of equations, we can use the method of substitution.
Step 1: Solve the first equation for y:
We have the equation 2y = 8. We can isolate y by dividing both sides of the equation by 2:
2y/2 = 8/2
y = 4
Step 2: Substitute the value of y into the second equation:
We have the equation 15y = 2x - 4. We will substitute y with 4:
15(4) = 2x - 4
60 = 2x - 4
Step 3: Solve the resulting equation for x:
Add 4 to both sides of the equation to isolate the term with 2x:
60 + 4 = 2x - 4 + 4
64 = 2x
Divide both sides of the equation by 2 to solve for x:
64/2 = 2x/2
32 = x
So, the solution to the system of equations is x = 32 and y = 4.