On heating 4 moles of pcl5 in cointainer 60percent of equlibrium then find the capacity of vessel
You need the equation, Kp or Kc, and the conditions (pressure and temperature).
.............PCl5 ==> PCl3 + Cl2
I...........4 mols......0.....0
C..........-2.4........2.4....2.4
E..........1.6.........2.4....2.4
At equilibrium, (PCl5) = 1.6/V
(PCl3) = 2.4/V
(Cl2) = 2.4/V
I don't really know the answer but can I ask 1 question??(Arjun from Rajkot genius school)
To find the capacity of the vessel, we need to determine the moles of PCl5 that will be present in equilibrium.
First, let's understand the given information. It states that on heating 4 moles of PCl5, the equilibrium will be 60% achieved. This means that only 60% of the PCl5 will react to form the products, while the remaining 40% will remain as PCl5.
Since the reaction involves PCl5, it is helpful to know the balanced equation for the reaction. The balanced equation for the reaction is:
PCl5(g) ⇌ PCl3(g) + Cl2(g)
According to the balanced equation, 1 mole of PCl5 reacts to form 1 mole of PCl3 and 1 mole of Cl2.
Now, let's calculate the moles of PCl5 that will remain in equilibrium:
Moles of PCl5 remaining = Initial moles of PCl5 - Moles of PCl5 reacted
= 4 moles - (4 moles * 0.60)
= 4 moles - 2.4 moles
= 1.6 moles
Therefore, 1.6 moles of PCl5 will remain in equilibrium.
Now, to find the capacity of the vessel, we need to calculate the volume of the vessel using the ideal gas equation:
PV = nRT
Assuming constant temperature and pressure, we can rearrange the equation to solve for V (volume):
V = nRT / P
where:
V = Volume of the vessel
n = moles of PCl5 remaining in equilibrium
R = Ideal gas constant (0.0821 L∙atm/(mol∙K))
T = temperature (in Kelvin)
P = pressure (in atmospheres)
Since we don't have the information about the temperature or pressure, we cannot determine the exact capacity of the vessel without that information.
In conclusion, the capacity of the vessel depends on the provided temperature and pressure, which are missing in the given information.