how many moles of cao are needed to react with excess water to produce 370 grams of calcium hydroxide
6.6 moles
What is cao? You won't get far in chemistry unless you find and use the caps key. Note that CO, Co, and co are different.
Do you mean CaO?
CaO + H2O ==> Ca(OH)2
mols Ca(OH)2 = grams/molar mass = ?
mols CaO = mols Ca(OH)2
i don't answer you
To determine the number of moles of CaO needed to react with excess water to produce 370 grams of calcium hydroxide (Ca(OH)2), we need to use the balanced chemical equation for the reaction and perform some calculations.
The balanced chemical equation for the reaction is as follows:
CaO + H2O -> Ca(OH)2
Step 1: Find the molar mass of Ca(OH)2
The molar mass of calcium hydroxide (Ca(OH)2) can be calculated by adding up the atomic masses of the individual elements:
Ca = 40.08 g/mol
O = 16.00 g/mol (2 oxygen atoms)
H = 1.01 g/mol (2 hydrogen atoms)
Molar mass of Ca(OH)2 = (40.08 + 16.00 + 1.01 + 1.01) g/mol = 74.10 g/mol
Step 2: Convert the given mass of Ca(OH)2 to moles
To do this, divide the given mass by the molar mass of Ca(OH)2:
Number of moles of Ca(OH)2 = 370 g / 74.10 g/mol ≈ 4.99 moles (rounded to two decimal places)
Step 3: Determine the stoichiometry between CaO and Ca(OH)2
Looking at the balanced chemical equation, we can see that 1 mole of CaO reacts with 1 mole of Ca(OH)2. This means that the number of moles of CaO required will be the same as the number of moles of Ca(OH)2.
Therefore, the number of moles of CaO needed to react with excess water to produce 370 grams of calcium hydroxide is approximately 4.99 moles.