She deposits $5 or $3.50 into her account. She made 14 deposits which equaled $59.50.
how many times did she deposit $5 & how many times did she deposit $3.50
- I don't know how to do this!
count the deposits, and count the amounts:
If there were x deposits at $5, and y at $3.50, then we know
x+y=14
5x+3.50y=59.50
Now just plug and chug.
8.5? Imma kinda confused on what numbers I need to multiply to get 59.50..
Steve said that x+y = 14..
Steve also explained to you.
*How are you confused on what numbers to multiply to get 59.50..?*
if x+y = 14 then it would be
x= 7
y=7
5x means 5 multiplied by x and x is 7.
5 times 7 is 35
so now its 35 + 3.50y
3.50 times 7 is 24.5
so now 35 + 24.5 = 59.5 or 59.50
Ohh okay. I get it now, thank you!
To solve this problem, we can use a system of equations. Let's assume that the number of times she deposited $5 is 'x', and the number of times she deposited $3.50 is 'y'.
We are given that she made 14 deposits, so we can write one equation as:
x + y = 14
We are also given that the total amount of all her deposits was $59.50, so we can write another equation as:
5x + 3.50y = 59.50
Now we have a system of two equations:
x + y = 14
5x + 3.50y = 59.50
To solve this system of equations, we can use several methods such as substitution or elimination. Let's use the elimination method:
Multiply the first equation by -3.50 so that the y terms will cancel out when we add the equations:
-3.50(x + y) = -3.50(14)
-3.50x - 3.50y = -49
Now add the two equations together:
(5x + 3.50y) + (-3.50x - 3.50y) = 59.50 - 49
5x - 3.50x + 3.50y - 3.50y = 10.50
Simplifying the equation gives us:
1.50x = 10.50
Divide both sides by 1.50 to solve for x:
x = 10.50 / 1.50
x = 7
Now, substitute the value of x in the first equation to solve for y:
7 + y = 14
y = 14 - 7
y = 7
Therefore, she deposited $5 seven times and $3.50 seven times.