What is slope of line 8y = -16?
a. 0
b. 2
c. 16
d. undefined
dont have a clue how to do this
recall that if the line is written in the form
y = mx + b, then m is the slope
so ...
8y = -16 or, how about
8y = 0x - 16
y = (0/8)x - 2
y = 0x - 2
so the slope must be 0
in general if the linear equation can be written in the form
y = k, where k is just a constant, you have a horizontal line and the slope is zero
if the linear equation can be written in the form
x = k , you have a vertical line and the slope is undefined.
Wasn't putting 0 in for slope...
thanks
To find the slope of a line, we need to rearrange the given equation in slope-intercept form, which is y = mx + b, where m represents the slope.
Given equation: 8y = -16
First, divide both sides of the equation by 8 to isolate y:
(8y)/8 = (-16)/8
Simplifying, we get:
y = -2
Now, we can see that the equation is in slope-intercept form, where the value of m (slope) is 0.
Therefore, the slope of the line represented by the equation 8y = -16 is a. 0.
To find the slope of a line, we need to rewrite the given equation into slope-intercept form, which is in the form of y = mx + b, where m represents the slope of the line.
Let's start by rearranging the equation 8y = -16:
Divide both sides of the equation by 8 to isolate y:
(8y)/8 = (-16)/8
y = -2
The equation is now in slope-intercept form: y = -2.
From this form, we can see that the slope, m, is equal to the coefficient of x, which is 0 in this case.
Therefore, the slope of the line 8y = -16 is 0.
Hence, the correct answer is option a. 0.