Which produces the greatest number of ions
when one mole dissolves in water?
(A) NaCl (B) NH4Cl
C) NH4NO3 (D) Na2SO4
To determine which compound produces the greatest number of ions when one mole dissolves in water, we need to consider the number of ions that each compound dissociates into.
Let's analyze each compound:
(A) NaCl: When NaCl dissolves in water, it dissociates completely into Na+ and Cl- ions. Therefore, one mole of NaCl produces two moles of ions (Na+ and Cl-).
(B) NH4Cl: When NH4Cl dissolves in water, it dissociates into NH4+ and Cl- ions. Therefore, one mole of NH4Cl produces two moles of ions (NH4+ and Cl-).
(C) NH4NO3: When NH4NO3 dissolves in water, it dissociates into NH4+ and NO3- ions. Therefore, one mole of NH4NO3 produces two moles of ions (NH4+ and NO3-).
(D) Na2SO4: When Na2SO4 dissolves in water, it dissociates into 2 Na+ ions and 1 SO4^2- ion. Therefore, one mole of Na2SO4 produces three moles of ions (2 Na+ and 1 SO4^2-).
Comparing the number of ions produced by each compound, we can see that Na2SO4 (D) produces the greatest number of ions when one mole dissolves in water.
The compound that produces the greatest number of ions when one mole dissolves in water is Na2SO4, option (D).
When Na2SO4 dissolves in water, it dissociates into two Na+ ions and one SO4^2- ion. Therefore, the total number of ions produced is three (2 Na+ ions + 1 SO4^2- ion).
On the other hand, options (A) NaCl, (B) NH4Cl, and (C) NH4NO3 each produce two ions when one mole dissolves in water.
NaCl dissociates into one Na+ ion and one Cl- ion, NH4Cl dissociates into one NH4+ ion and one Cl- ion, and NH4NO3 dissociates into one NH4+ ion and one NO3- ion.
Hence, the compound Na2SO4 produces the greatest number of ions when one mole dissolves in water.
How do these things ionize?
NaCl ==> Na^+ + Cl^-. Two ions produced
NH4Cl ==> NH4^+ + Cl^-. Two ions.
You do the others. I'll be glad to check your work.