When Mg reacts with HCl, it produces MgCl2 and H2(g). If 2.34 g of Mg react, how much MgCl2 is produced (in grams)?
Mg + 2HCl ==> MgCl2 + H2
mols Mg = grams/molar mass = ?
Using the coefficients n the balanced equation, convert mols Mg to mols MgCl2.
Now convert mols MgCl2 to grams. g = mols MgCl2 x molar mass Mgcl2.
To find the amount of MgCl2 produced, we need to use the concept of stoichiometry.
Stoichiometry is a quantitative relationship between the amounts of reactants and products in a chemical reaction. In this case, we need to determine the stoichiometric ratio between Mg and MgCl2 in the given reaction.
The balanced equation for the reaction is:
Mg + 2HCl -> MgCl2 + H2
From the balanced equation, we see that one mole of Mg reacts with one mole of MgCl2.
To find the number of moles of Mg, we need to use the molar mass of Mg. The molar mass of Mg is approximately 24.31 g/mol.
Given that we have 2.34 g of Mg, we can calculate the number of moles of Mg using the formula:
moles of Mg = mass / molar mass
moles of Mg = 2.34 g / 24.31 g/mol
moles of Mg ≈ 0.096 moles
Since the stoichiometric ratio between Mg and MgCl2 is 1:1, the number of moles of MgCl2 produced will be the same as the number of moles of Mg.
So, the number of moles of MgCl2 produced is approximately 0.096 moles.
To find the mass of MgCl2 produced, we need to use the molar mass of MgCl2. The molar mass of MgCl2 is approximately 95.21 g/mol.
mass of MgCl2 = moles of MgCl2 * molar mass
mass of MgCl2 = 0.096 moles * 95.21 g/mol
mass of MgCl2 ≈ 9.15 g
Therefore, approximately 9.15 grams of MgCl2 is produced when 2.34 grams of Mg reacts with HCl.