What is the molality of 67.1g of Nano3 in 2.5l of water
mols NaNO3 = grams/molar mass
Then m = mols/kg solvent.
2.5 L is 2.5 kg if the density of H2O is 1.00 g/mL.
is finding the molality and molarity the same concept
To calculate the molality (m) of a solute in a solvent, you need to know the moles of solute and the mass of the solvent.
First, we need to find the moles of NaNO3. The molar mass of NaNO3 is 85 grams/mol.
molar mass of NaNO3 = 22.99 (atomic mass of Na) + 14.01 (atomic mass of N) + 3 * 16 (3 times the atomic mass of O) = 85 grams/mol
To find the moles of NaNO3, divide the given mass of NaNO3 by its molar mass:
moles of NaNO3 = mass of NaNO3 / molar mass of NaNO3 = 67.1 g / 85 g/mol.
Next, we need to find the mass of the water in kilograms since molality is defined as the number of moles of solute per kilogram of solvent:
mass of water = 2.5 L * 1 kg/L = 2.5 kg
Finally, we can calculate the molality by dividing the moles of NaNO3 by the mass of water in kilograms:
molality (m) = moles of NaNO3 / mass of water in kg.
Now, you can substitute the values we found into the formula to find the molality.