The function f(t)=37sin(pi/3 -5)+81 is used to represent the changes in temperature of a chemical compound used in a lab. What is the amplitude?
I got 5, is this correct.
I have the options of 81, 5, 6pi, 37, and 2
no, the amplitude is the coefficient out front: 37
You know the amplitude of sin(x) is 1
5 in this case isn't really anything. It might look like a phase shift, but it's not even that.
And you still have a typo, since there's no t anywhere on the right side. You just have a constant.
To find the amplitude of a sinusoidal function, we need to look at the coefficient multiplying the sine function. In this case, the function is f(t) = 37sin(pi/3 - 5) + 81.
The coefficient in front of the sine function is 37. Therefore, the amplitude of the function is 37.
So, your answer of 5 is not correct. The correct answer is 37.