How long would it take for a ball dropped from the top of a 256-foot building to hit the ground?
256 = (1/2)(32) t^2
because 32 ft/s^2 is g in obsolete units which no one but math teachers remember.
12
To determine the time it would take for a ball to hit the ground when dropped from a height, we can use a simple physics equation. The equation is derived from the principles of motion under gravity:
h = (1/2) * g * t^2
Where:
h = height or distance traveled by the object (in this case, the height of the building)
g = acceleration due to gravity (approximately 32.2 feet/second^2)
t = time taken
We need to rearrange the equation to solve for time (t):
t^2 = (2 * h) / g
Substituting the given values, we have:
t^2 = (2 * 256) / 32.2
t^2 = 16
To find the time, we take the square root of both sides:
t = √(16)
t = 4 seconds
Therefore, it would take approximately 4 seconds for the ball to hit the ground when dropped from the top of a 256-foot building.