math
posted by Anonymous
the sum of the ages of sam and tomas is 27 years. seven years ago, tomas was three years more than onefourth as old as sam. find their present age

Reiny
Let Sam's age 7 years ago be s
let Tom's age 7 years ago be t
So
s+7 + t+7 = 27
s+t = 13 > t = 13s
"seven years ago, tomas was three years more than onefourth as old as sam"
 t = (1/4)s + 3
13s = (1/4)s + 3
times 4
52  4s = s + 12
5s = 40
s = 8
so 7 years ago Sam was 8 and Tom was 5
So NOW they are 15 and 12
Check :
is the sum of their present ages 27
15+12 = 27 , check!
7 years ago, is Tom 3 more than 1/4 of Sam's age
1/4 of Sam= 2
3 more than that is 5, which was Tom's age, check!!
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