Iron and oxygen gas can react to form the magnetic oxide of iron Fe3O4. How many grams of Fe3O4 can be made from 13.2 g of O2?
1. Write and balance the equation.
3Fe + 2O2 ==> Fe3O4
2. Convert grams O2 to mols. mols = grams/molar mass = ?
3. Using the coefficients in the balanced equation, convert mols O2 to mols Fe3O4. That's ?mols O2 from step 2 x (1 mol Fe3O4/2 mols O2) = ? mols O2 x (1/2) = ?
4. Now convert mols Fe3O4 to grams. g = mols x molar mass.
To find the mass of Fe3O4 that can be produced from 13.2 g of O2, we need to determine the stoichiometry of the reaction and calculate the molar mass of Fe3O4.
The balanced equation for the reaction is:
4 Fe + 3 O2 -> 2 Fe3O4
From this equation, we can see that it takes 3 moles of O2 to react with 4 moles of Fe to produce 2 moles of Fe3O4.
To calculate the number of moles of O2 in 13.2 g, we need to divide the mass by the molar mass of O2. The molar mass of O2 is 32.00 g/mol.
Number of moles of O2 = Mass / Molar Mass
= 13.2 g / 32.00 g/mol
≈ 0.4125 mol
Now, using the stoichiometry of the reaction, we can determine the number of moles of Fe3O4 produced from the given amount of O2.
Number of moles of Fe3O4 = (2/3) * Number of moles of O2
= (2/3) * 0.4125 mol
≈ 0.275 mol
Finally, we can calculate the mass of Fe3O4 using its molar mass. The molar mass of Fe3O4 is calculated as follows:
(3 x molar mass of Fe) + (4 x molar mass of O)
= (3 x 55.85 g/mol) + (4 x 16.00 g/mol)
= 167.55 g/mol
Mass of Fe3O4 = Number of moles of Fe3O4 * Molar mass
= 0.275 mol * 167.55 g/mol
≈ 45.98 g
Therefore, approximately 45.98 grams of Fe3O4 can be produced from 13.2 grams of O2.
To determine the number of grams of Fe3O4 that can be made from 13.2 g of O2, we need to first establish a balanced chemical equation for the reaction between iron and oxygen.
The balanced chemical equation for the reaction is:
4 Fe + 3 O2 -> 2 Fe3O4
From the equation, we can see that 4 moles of Fe react with 3 moles of O2 to produce 2 moles of Fe3O4.
Step 1: Calculate the molar mass of O2
The molar mass of O2 is calculated by adding up the atomic masses of each element in the compound:
Molar mass of O2 = 2 × (Atomic mass of O)
= 2 × 16.00 g/mol
= 32.00 g/mol
Step 2: Convert grams of O2 to moles
To convert grams to moles, we divide the given mass by the molar mass:
Moles of O2 = Mass of O2 / Molar mass O2
= 13.2 g / 32.00 g/mol
≈ 0.4125 mol
Step 3: Determine the moles of Fe3O4 that can be produced
From the balanced equation, we know that 4 moles of Fe react with 3 moles of O2 to produce 2 moles of Fe3O4. Therefore, the moles of Fe3O4 produced will be proportional to the moles of O2.
Moles of Fe3O4 = (2/3) × Moles of O2
= (2/3) × 0.4125 mol
≈ 0.275 mol
Step 4: Calculate the molar mass of Fe3O4
The molar mass of Fe3O4 can be calculated by adding up the atomic masses of each element in the compound:
Molar mass of Fe3O4 = (Atomic mass of Fe × 3) + (Atomic mass of O × 4)
= (55.85 g/mol × 3) + (16.00 g/mol × 4)
= 159.70 g/mol
Step 5: Convert moles of Fe3O4 to grams
To convert moles to grams, we multiply the number of moles by the molar mass:
Mass of Fe3O4 = Moles of Fe3O4 × Molar mass of Fe3O4
= 0.275 mol × 159.70 g/mol
≈ 43.92 g
Therefore, approximately 43.92 grams of Fe3O4 can be made from 13.2 grams of O2.