A mixture of gases contains 2.41 moles of O2, 1.24 moles of H2 and 1.92 moles of C. Calculate the partial pressure of gases if the total pressure is 3.0 atm

I wonder if you meant CO2 instead of C. T must be pretty high to have C has a gas.

Total mols = sum mols of each gas.
Then XO2 = nO2/total mols
XH2 = nH2/total mols
XC = nC/total mols.

Then pO2 = XO2*Ptotal = ?
pH2 = XH2*Ptotal
pC = XC*Ptotal

To calculate the partial pressure of each gas, we will use the concept of the mole fraction. The mole fraction of a gas is defined as the ratio of the number of moles of that gas to the total number of moles in the mixture. The mole fraction, denoted by 'X', can be calculated using the formula:

X = (moles of gas / total moles of all gases)

First, let's calculate the total number of moles in the mixture:
Total moles = moles of O2 + moles of H2 + moles of C
Total moles = 2.41 moles + 1.24 moles + 1.92 moles
Total moles = 5.57 moles

Now, we can calculate the mole fraction of each gas:

Mole fraction of O2 = (moles of O2 / total moles)
Mole fraction of O2 = 2.41 moles / 5.57 moles

Mole fraction of H2 = (moles of H2 / total moles)
Mole fraction of H2 = 1.24 moles / 5.57 moles

Mole fraction of C = (moles of C / total moles)
Mole fraction of C = 1.92 moles / 5.57 moles

Next, we will multiply each mole fraction by the total pressure to obtain the partial pressure of each gas.

Partial pressure of O2 = Mole fraction of O2 × Total pressure
Partial pressure of O2 = (2.41 moles / 5.57 moles) × 3.0 atm

Partial pressure of H2 = Mole fraction of H2 × Total pressure
Partial pressure of H2 = (1.24 moles / 5.57 moles) × 3.0 atm

Partial pressure of C = Mole fraction of C × Total pressure
Partial pressure of C = (1.92 moles / 5.57 moles) × 3.0 atm

Calculating these expressions will give you the partial pressure of each gas.