calculate the oh- and h3o+ concentration of a solution that as ph of 12.11. is the soluion acidic, basic or neutral. report you answer to 2 significant figure

To calculate the OH- and H3O+ concentrations of a solution, we can use the relationship between pH and the concentration of H3O+ ions. The equation for pH is defined as:

pH = -log[H3O+]

To find the concentration of H3O+ ions, we need to rearrange the equation:

[H3O+] = 10^(-pH)

Given that the pH of the solution is 12.11, we can calculate the concentration of H3O+:

[H3O+] = 10^(-12.11)
[H3O+] ≈ 7.24 x 10^(-13)

Since the solution is not neutral (pH of 7), the H3O+ concentration is less than 1 x 10^(-7) M, indicating that the solution is basic.

To determine the OH- concentration, we can use the fact that in any aqueous solution, the product of the H3O+ and OH- concentrations must always equal a constant, known as the ion product of water.

[H3O+] x [OH-] = 1 x 10^(-14) M^2

Since we now know the H3O+ concentration, we can rearrange the equation to solve for the OH- concentration:

[OH-] = 1 x 10^(-14) / [H3O+]
[OH-] ≈ 1.38 x 10^(-2) M

Thus, the OH- concentration is approximately 1.38 x 10^(-2) M.

Reporting both answers to two significant figures:

[H3O+] ≈ 7.2 x 10^(-13) M
[OH-] ≈ 1.4 x 10^(-2) M

Therefore, the OH- and H3O+ concentrations of the solution with a pH of 12.11 are approximately 1.4 x 10^(-2) M and 7.2 x 10^(-13) M, respectively. The solution is basic.

You really should find the caps key on your keyboard and USE it.

pH = -log(H^+).
Substitute and solve for (H^+).
Then (H^+)(OH^-) = Kw = 1E-14.
Substitute and solve for OH^-.
Neutral is pH = 7
acid is pH < 7
basic is pH > 7