Evaluate 2/(1+J4)^2
I got as far as:
(1+j4)^2=(1+j4)(1+j4)=1+j4+j4+j4^2=1+J24
OR
(1+j4)^2 (/2)
=(0.25+j)(0.25+j)=0.0625+j+j+j^2
=0.0625+j+j-0.0625=J^2
I think it can be take further. but im not sure i'm right.
NVM i think i've done it. I simplified to -2(15+8J)/-289
correct if i'm wrong please!
The bottom is +289
To evaluate `(1+j4)^2` and simplify the expression further, let's break it down step by step:
Step 1: Expand the square
(1+j4)^2 = (1+j4)(1+j4)
Using the distributive property, multiply the terms:
= 1 + j4 + j4 + j4^2
Step 2: Simplify j4^2
Since j is defined as √(-1), j^2 can be substituted with -1:
= 1 + j4 + j4 + (-1)
= 1 + 2j4 - 1
= 2j4
Now, we have the simplified expression: 2j4
Step 3: Evaluate the expression `2j4`
Remember that j4 means j*j*j*j. So, let's simplify further:
2j4 = 2(j*j*j*j)
= 2(j^4)
Since j^4 = (j^2)^2, and j^2 = -1, we can substitute this back in:
= 2((-1)^2)
= 2(1)
= 2
Therefore, the final evaluation of the expression `(1+j4)^2` is 2.