Two artifacts in a museum display are hung from vertical walls by very light wires. Wire T1 is horizontal from the left wall and goes to a center weight of 177N and wire T2 is at a 53 degree angle with the right wall heading from right to left downwards towards the center weight of 177N. From the center weight a wire T3 hangs vertically to a 40kg object.
Find the tension on T1, T2 and T3.
T3 solved but don't know how to calc. T1 and T2.
Got an answer and that is much appreciated but I don't think that it applied properly to my question.
Look up this question on google and you can get a diagram that may better help someone explain how to get T1 horizontal tension and T2 incline tension.
Still need the help please.
To find the tensions in wires T1 and T2, we can use the principles of equilibrium, which state that the net force and net torque acting on a system are zero.
First, let's assume that the weight of each wire is negligible compared to the other forces involved. This assumption allows us to consider only the tensions in the wires and the weight of the central object.
To find the tension in wire T1, we can consider the forces acting in the horizontal direction. Since wire T1 is horizontal, its tension only acts vertically. Therefore, the tension in T1 is equal to the weight of the central object, which is 40 kg multiplied by the acceleration due to gravity (9.8 m/s^2):
T1 = (40 kg)(9.8 m/s^2) = 392 N
Next, let's find the tension in wire T2. We can consider the forces acting in the vertical direction. The vertical component of the tension in T2 counteracts the weight of the central object (40 kg) and the weight of the central weight (177 N). Thus, we can write the equation:
T2cos(53°) = (40 kg + 177 N)
T2 = (40 kg + 177 N)/cos(53°)
Using a calculator, we can find the value of T2.
Please note that the diagram you mentioned would be helpful to visualize the arrangement of the wires and objects accurately.